[DeTomaso] Spring rates, math quiz

Paul Timko thedrol at pobox.com
Fri Jun 13 16:32:10 EDT 2014


Ken's comments are correct.  The shocks are usually installed on an 
angle (I haven't actually seen a Longchamp, so I'm not positive), so a 
1cm reduction in spring height results in less than a 1cm reduction in 
ride height.

Paul
#9270

On 6/13/2014 3:16 PM, Mikael wrote:
>     No spacers
>
>     Sent from my BlackBerry Q10
>
>     From: Ken Green
>     Sent: fredag den 13. juni 2014 22.14
>     To: Mikael; Mike Thomas; 'De Tomaso List'
>     Reply To: Ken Green
>     Subject: Re: [DeTomaso] Spring rates, math quiz
>
>     I don't think you necessarily lower the car 1cm if the compressed
>     spring is 1 cm shorter, depends on the suspension geometry.
>     Are you sure there are no spacers in the shocks you can remove, like
>     the spacers on Pantera shocks?  If there are, do that first.
>     Ken
>     From: Mikael <mikael_hass at mail.tele.dk>
>     To: Mike Thomas <mbefthomas at comcast.net>; 'De Tomaso List'
>     <detomaso at poca.com>
>     Sent: Friday, June 13, 2014 12:30 PM
>     Subject: [DeTomaso] Spring rates, math quiz
>     So all you math genuises, here's a question. My orig Longchamp springs
>     of unknown spring rate are too hard/long now that I have replaced heavy
>     iron: headers, heads, intake. Tomorrow I'm going to a place where they
>     have springs on shelves so I can measure and find close origs in size.
>     I.D. has to be exact (9cm). And I plan to find springs from a car with
>     a V6, preferably sporty soo not too soft. And I realize that I will
>     have to buy several (they're about $60 each) to experiment to get the
>     height I want.
>     But here's the question. Orig springs are 38cm free, and 25cm mounted
>     in shock and weight on car. I'm looking for around 20cm, lowering 5cm.
>     Question: if they have springs with proper diameter, but are maybe 33cm
>     at rest instead of 38cm, what is the equivalent height decrease when
>     weight is on spring and mounted in shock? Is there a formula?
>     Sent from my BlackBerry Q10
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