[DeTomaso] Spring rates, math quiz

[Mikael]

   No spacers

   Sent from my BlackBerry Q10

   From: Ken Green
   Sent: fredag den 13. juni 2014 22.14
   To: Mikael; Mike Thomas; 'De Tomaso List'
   Reply To: Ken Green
   Subject: Re: [DeTomaso] Spring rates, math quiz

   I don't think you necessarily lower the car 1cm if the compressed
   spring is 1 cm shorter, depends on the suspension geometry.
   Are you sure there are no spacers in the shocks you can remove, like
   the spacers on Pantera shocks?  If there are, do that first.
   Ken
   From: Mikael <mikael_hass at mail.tele.dk>
   To: Mike Thomas <mbefthomas at comcast.net>; 'De Tomaso List'
   <detomaso at poca.com>
   Sent: Friday, June 13, 2014 12:30 PM
   Subject: [DeTomaso] Spring rates, math quiz
   So all you math genuises, here's a question. My orig Longchamp springs
   of unknown spring rate are too hard/long now that I have replaced heavy
   iron: headers, heads, intake. Tomorrow I'm going to a place where they
   have springs on shelves so I can measure and find close origs in size.
   I.D. has to be exact (9cm). And I plan to find springs from a car with
   a V6, preferably sporty soo not too soft. And I realize that I will
   have to buy several (they're about $60 each) to experiment to get the
   height I want.
   But here's the question. Orig springs are 38cm free, and 25cm mounted
   in shock and weight on car. I'm looking for around 20cm, lowering 5cm.
   Question: if they have springs with proper diameter, but are maybe 33cm
   at rest instead of 38cm, what is the equivalent height decrease when
   weight is on spring and mounted in shock? Is there a formula?
   Sent from my BlackBerry Q10
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