[DeTomaso] charging problems

[SOBill at aol.com]

Mark,
 
The "blue" wire should be a Blue/Black wire which comes the charge  
indicator in the speedo. With the wire disconnected from the regulator 12V would  
be normal. With the wire connected to the regulator 1.9V could be normal as 
this  would be the starting voltage across the alternator field windings.
 
Attached are the diagram the battery charging circuit and a detailed  
description of how it works. If it is not clear how the charging system works,  
let me know.
 
Measure the voltage on the Yellow wire at the regulator. This must be the  
battery voltage. This wire provides a sample of the battery voltage to the  
regulator and provides the field excitation when the alternator starts 
putting  out serious current. The yellow wire must be connected to the starter 
solenoid  terminal which has the cable direct from the battery.
 
You can very quickly verify that the alternator will put out charging  
current: jumper the Yellow wire to the Orange wire at the regulator. This  will 
apply 12V to the field winding and the alternator and the alternator will  
put out max voltage and current when the engine is running. I would only do 
this  as a very short test and would best be done with one person in the car 
with the  engine running and an eye on the ammeter and another person just 
touching the  two wires together. This completely eliminates the regulator 
and drives the  alternator to max voltage output.
 
Let me know what you find.
 
 
SOBill
 
The main  thing is to keep the main thing the main thing.
Do the best you can with what  your have where you are.
Have fun today!
SOBill  

 
In a message dated 9/12/2014 12:03:23 P.M. Pacific Daylight Time,  
ehpantera at yahoo.com writes:

 
I've cleaned all the wire ends and grounds. Made a new ground from  
regulator base to Alt. case.


I have 12 volts to the regulator (blue wire) when it is not  connected to 
the regulator. When I connect it to the regulator the voltage  drops to 1.9 
volts. I suspect this is the problem area Solutions?
Mark




 






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   Mark,



   The "blue" wire should be a Blue/Black wire which comes the charge
   indicator in the speedo. With the wire disconnected from the regulator
   12V would be normal. With the wire connected to the regulator 1.9V
   could be normal as this would be the starting voltage across the
   alternator field windings.



   Attached are the diagram the battery charging circuit and a detailed
   description of how it works. If it is not clear how the charging system
   works, let me know.



   Measure the voltage on the Yellow wire at the regulator. This must be
   the battery voltage. This wire provides a sample of the battery voltage
   to the regulator and provides the field excitation when the alternator
   starts putting out serious current. The yellow wire must be connected
   to the starter solenoid terminal which has the cable direct from the
   battery.



   You can very quickly verify that the alternator will put out charging
   current: jumper the Yellow wire to the Orange wire at the regulator.
   This will apply 12V to the field winding and the alternator and the
   alternator will put out max voltage and current when the engine is
   running. I would only do this as a very short test and would best be
   done with one person in the car with the engine running and an eye on
   the ammeter and another person just touching the two wires together.
   This completely eliminates the regulator and drives the alternator to
   max voltage output.



   Let me know what you find.





   SOBill



   The main thing is to keep the main thing the main thing.
   Do the best you can with what your have where you are.
   Have fun today!
   SOBill

   In a message dated 9/12/2014 12:03:23 P.M. Pacific Daylight Time,
   ehpantera at yahoo.com writes:

   I've cleaned all the wire ends and grounds. Made a new ground from
   regulator base to Alt. case.
   I have 12 volts to the regulator (blue wire) when it is not connected
   to the regulator. When I connect it to the regulator the voltage drops
   to 1.9 volts. I suspect this is the problem area Solutions?
   Mark
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