[DeTomaso] Starter Replacement Options

[MikeLDrew at aol.com]

In a message dated 5/1/14 9 24 21, forestg at att.net writes:


> If you do this the starter will run on after releasing the key from the 
> start position leading to damage to the starter.
> 

>>>Uh...what?

The main battery cables from the battery to the starter are connected on 
the non-switched side of the stock solenoid.   The only function here is to 
serve as a connector for the two cables (and provide power for the solenoid).

When the key is turned, the voltage crosses the stock solenoid and goes to 
the output lug.   In the past, this voltage then went down to the starter 
via the thick cable, but now a smaller wire is the only thing on this lug, and 
the power goes to the solenoid on the new starter, activating it.

As soon as you release the key from the spring-loaded 'start' position, 
power across the stock solenoid is interrupted, meaning that power from the 
output side lug to the solenoid on the new starter is interrupted.

So, there is no way for the starter to 'run on' as you suggest.

Mike (been wired this way for years, and no I'm not smart enough to figure 
this stuff out on my own, I read the diagram that came with the starter...) 
:>)
-------------- next part --------------
   In a message dated 5/1/14 9 24 21, forestg at att.net writes:

     If you do this the starter will run on after releasing the key from
     the start position leading to damage to the starter.

   >>>Uh...what?
   The main battery cables from the battery to the starter are connected
   on the non-switched side of the stock solenoid.  The only function here
   is to serve as a connector for the two cables (and provide power for
   the solenoid).
   When the key is turned, the voltage crosses the stock solenoid and goes
   to the output lug.  In the past, this voltage then went down to the
   starter via the thick cable, but now a smaller wire is the only thing
   on this lug, and the power goes to the solenoid on the new starter,
   activating it.
   As soon as you release the key from the spring-loaded 'start' position,
   power across the stock solenoid is interrupted, meaning that power from
   the output side lug to the solenoid on the new starter is interrupted.
   So, there is no way for the starter to 'run on' as you suggest.
   Mike (been wired this way for years, and no I'm not smart enough to
   figure this stuff out on my own, I read the diagram that came with the
   starter...) :>)