[DeTomaso] Spring rates, math quiz

[Paul Timko]

It depends on the spring rate (lbs/in) which is based on the number of 
turns and the metal of the springs.  So there isn't really a good 
answer.  Particularly since they make springs that have the same 
uncompressed length and diameter with different spring rates.

Paul
#9270

On 6/13/2014 2:30 PM, Mikael wrote:
>
> So all you math genuises, here's a question. My orig Longchamp springs of unknown spring rate are too hard/long now that I have replaced heavy iron: headers, heads, intake. Tomorrow I'm going to a place where they have springs on shelves so I can measure and find close origs in size. I.D. has to be exact (9cm). And I plan to find springs from a car with a V6, preferably sporty soo not too soft. And I realize that I will have to buy several (they're about $60 each) to experiment to get the height I want.
>
> But here's the question. Orig springs are 38cm free, and 25cm mounted in shock and weight on car. I'm looking for around 20cm, lowering 5cm. Question: if they have springs with proper diameter, but are maybe 33cm at rest instead of 38cm, what is the equivalent height decrease when weight is on spring and mounted in shock? Is there a formula?
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