[DeTomaso] DeTomaso caster

[David_Bell at oxy.com]

The sum of the 7/16" offset at the top and the opposite 7/16" offset at
the bottom is 14/16", or 0.875".  Measure the vertical distance between
the two pivot points (a-arms).  I don't have access to my car at the
moment but let's assume this distance is nine inches.  Assuming the
spindle was originally perpendicular to the ground surface, then the new
caster angle would be inverse sin of (0.875 / 9.0), or 5.6 degrees.  If
the upper and lower a-arm separation was 12" instead of 9", then the
caster angle would drop to 4.2 degrees using the same 7/16" offset.


Dave Bell 



-----Original Message-----
From: detomaso-bounces at realbig.com
[mailto:detomaso-bounces at realbig.com]On
Behalf Of RTASPL at aol.com
Sent: Wednesday, May 02, 2007 12:42 AM
To: detomaso at realbig.com
Subject: Re: [DeTomaso] DeTomaso caster

If I can move the lower control arm to the front 7/16 of an inch. And
the
upper control arm back 7/16 of an inch. What amount of total caster do
you
think
 I will gain?     Todd Reid



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